11t^2-24t+4=0

Solution for 11t^2-24t+4=0 equation:

11t^2-24t+4=0

a = 11; b = -24; c = +4;
Δ = b2-4ac
Δ = -242-4·11·4
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-20}{2*11}=\frac{4}{22}
=2/11
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+20}{2*11}=\frac{44}{22}
=2
$